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Two types of plastic are suitable for use by an electronic calculator manufacturer. The breaking strength of this plastic is important. It is known that V1= V2= 1.0 psi. From random samples of n1= 10and n2= 12 we obtain y1= 164.5 and y2= 155.0. The company will not adopt plastic 1 unless its breaking strength exceeds that of plastic 2 by at least 10 psi. Based on the sample information, should they use plastic 1? In answering this questions, set up and test appropriate hypotheses using D = 0.01. Construct a 99 percent confidence interval on the true mean difference in breaking strength.

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