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Probability based on Normal distribution:

The average amount customers at a certain grocery store spend yearly is $636.55. Assume the variable is normally distributed. If the standard deviation is $89.46, find the probability that a randomly selected customer spends between $550.67 and $836.94.

a) 0.144 = 14.4%

b) 0.820 = 82.0%

c) 0.156 = 15.6%

d) 0.943 = 94.3%

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