Create the 99 confidence interval on difference of average, Ask an Expert

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Advertisers analyze average age of viewers of TV programs. For instance, 60 Minutes reportedly has one of highest average ages at 57. Assume that marketing analyst believes that age gap between 60 Minutes and Star Trek: Voyager has narrowed to less than historical 15 years. Random sample of 100 viewers from each of TV programs was selected and results are as follows:

60 Minutes: Sample Mean = 55.6 Population standard deviation = 10.8, Sample size = 100. Star Trek: Voyager: Sample Mean = 41.8, Population standard deviation = 7.9, Sample size = 100.

A. Create the 99% confidence interval on difference of average ages for viewers of the two TV programs. How can you interpret interval?

B. Test hypothesis that difference in average age of viewers for these two programs is less than 15 years. Make use of significance level of 1%.

C. Why can you not use confidence interval in part A to test hypothesis in part B?

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