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A testing device is claimed to have high reliability insofar as: P[A/B]=P[Acomplement/Bcomplement] =p where A=device indicates component is faulty and B=component is faulty. Suppose 5% of components are faulty in a large batch of components and the reliability is p=0.95

a. Prove that P[Acompliment/B] =1 - P[A/B] {hint : P[S/B] with S=A U Acomplement }

b. Use bayes theorem to compute P[B/A] and indicate what this result suggest in practical terms

c. Suppose P[B/A] =0.9 is required. Find p

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Statistics and Probability, Statistics

Category:- Statistics and Probability
Reference No.:- M9992516

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