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A sample of 100 families was drawn for analysis of the average grocery spending. Assume that the individual weekly expences are normally distributed, with the unknown population average and population standard deviation of $50. Sample summaries were: (Sample Mean) = $132.50 and Sample Standard Deviation = $56

Estimate the population average with the 95% confidence.

Mid-Point =

Standard Deviation of Sample Mean =

Critical Value =

Margin of Error =

Upper Confidence Limit =

Lower Confidence Limit =

Width of the interval =

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Statistics and Probability, Statistics

Category:- Statistics and Probability
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