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A 99% confidence interval for the proportion () of all Lewisburg residents whose annual income exceeds $80,000 extends from 0.10 to 0.18. The confidence interval is based on a random sample of 150 Lewisburg residents. Using this information and a 1% level of significance, we wish to test the following hypotheses:

H0: 0.08
Ha: 0.08

Based on the given information, what is the correct statistical decision in this case? Explain your recommendation.

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Statistics and Probability, Statistics

Category:- Statistics and Probability
Reference No.:- M9438201

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