(Answered) In a random sample ofnbsp50nbsprefrigerators the mean

Economics

In a random sample of 50 ?refrigerators, the mean repair cost was ?$146.00 and the population standard deviation is ?$17.80.

Construct a 90?% confidence interval for the population mean repair cost. Interpret the results.

Construct a 90% confidence interval for the population mean repair cost. The 90?% confidence interval is ( ? , ? ). ?(Round to two decimal places as? needed.)

Interpret you results. Choose the correct answer below.

A.With 90?% ?confidence, it can be said that the confidence interval contains the true mean repair cost.

B.With 90?% ?confidence, it can be said that the confidence interval contains the sample mean repair cost.

C.The confidence interval contains 90% of the mean repair costs.

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