a. Ba(NO3)2 + 2 NH2SO3H + 0 H2O = Ba(NH2SO3)2 + 2 HNO3
b. Ba(NO3)2 + NH2SO3H + H2O = BaSO4 + NH4NO3 + HNO3
c. Ba(NO3)2 + 2 NH2SO3H + 2 H2O = Ba(NH2)2 + 2 H2SO4 + 2HNO3

1. When a solution containing 1.4 g of Ba(NO3)2 and 2.4 g ofNH2SO3H is boiled, a precipitate forms. This precipitate maybe Ba(NH2SO3)2, BaSO4, or Ba(NH2)

2. Calculate the number of molesof each reactant.

3. Determine the limiting reactant in each of the following three reactions. The limiting reactant that you determine here will be used directly in this experiment.

Reaction producing Ba(NH2SO3)2:

Reaction producing BaSO4:

Reaction producing Ba(NH2)2:

4. What conclusion can you reach about the limiting reactant in this experiment?